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7p^2+2p-104=0
a = 7; b = 2; c = -104;
Δ = b2-4ac
Δ = 22-4·7·(-104)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2916}=54$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-54}{2*7}=\frac{-56}{14} =-4 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+54}{2*7}=\frac{52}{14} =3+5/7 $
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